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A charge of 1 coul. is placed at one end of a non-conducting rod of length 0.6m. the rod is rotated in a vertical plane about a horizontal axis passing through the other end of the rod with angular frequency 104πradian/sec. Find the magnetic field at a point on the axis of rotation at a distance of 0.8 from the centre of the path. Now half of the charge is removed from one end and placed on the other end. The rod is rotated in a vertical plane about horizontal axis passing through the mid-point of the rod with the same angular frequency. Calculate the magnetic field at a point on the axis at a distance of 0.4m form the centre of the rod.

Two slits 4.0×10−6m apart are illuminated by light of wavelength 600nm. What is the highest order fringe in the interference pattern?

Find the amplitude of the electric field in a parallel beam of light of intensity 8.0Wm−2.

The departure from the 1/r^2 dependence of the flux of alpha particles scattered at an angle of 60°, expected from Rutherford Scattering, that was first measured by Eisberg et al (see notes), could be interpreted classically as due to the partial penetration of alpha particles into the nucleus. Although neglecting the strong nuclear interaction (which acts in addition to Coulomb scattering), this led to a not unreasonable estimate of 1.2 fm for the radius of the Pb lead target nuclei, which was later shown to be ~50% too large. With the help of the expression for the electric potential V(r) (SI units: Joules/Coulomb or equivalently Volts) outside and inside a uniformly charged sphere derived overleaf:(i) Determine the maximum energy in MeV of non-relativistic alpha particles, which may be assumed to be point charges, that will be back-scattered by a 20 Pb nucleus, assumed to be a uniformly charged sphere, of radius 1.2 fm fixed in space when the impact parameter is zero. (Hint: First understand why there is a maximum energy in the case of a target nucleus of finite radius).(ii) The log plot reproduced in the notes from Eisberg et al shows a steep decrease in the alpha particle flux above E=27.5 MeV for a 60° scattering angle. With the insight gained from answering part (i), derive an upper limit for the alpha particle energy at which the flux at scattering angle vanishes for a finite nuclear radius R, and evaluate it at θ=60° for the Pb nucleus. (Hint: Consider the potential energy available at the edge of the nucleus that will cause the alpha particle to cease its vertical motion. You may assume the direction of motion at the edge of the nucleus is unchanged from its remote value of 0°. This assumption is not too bad for energetic particles for which d<

Texts: a. Consider an electron in an infinite square well of width a = 15 fm. In an ensemble energy measurement at t = 0, we find that the value 2h/ma with 0.36 possibility and the value 25h/2ma with 0.64 possibility. Write down the time-independent and time-dependent wave functions of this system.ψ(x, t) = Σ Cnψn(x)e^(-iEn t/ħ)Where:ψn(x) = √(2/a) sin(nπx/a)En = (n^2π^2ħ^2)/(2ma^2)b. i. dB = [HB] An electron in an oscillating electric field is described by the Hamiltonian:H = (1/2m)(p - eA)^2Where:p = -iħ∇A = A0sin(ωt)ii. The time-dependent Schrödinger equation for this system is:iħ∂ψ/∂t = Hψ

help !51.(A) The radius of a 27Mg nucleus can be estimated to be (@) 2.86 10-13 cm (b) 5.210-13 cm (c) 3.6 10-13 cm (d) 8.6 10-13 cm (B) The root-mean-square (rms) energy of a nucleon in a nucleus of atomic number A in state varies as a)A4/3 (b) A1/3 (c) A-1/3 (d)A-2/3

The equivalent capacitance between A and B terminals.